WELCOME TO FRENDZ4M
Tue, Dec 3, 2024, 10:55:06 PM

Current System Time:

Get updatesShare this pageSearch
Telegram | Facebook | Twitter | Instagram Share on Facebook | Tweet Us | WhatsApp | Telegram
 

Forum Main>>General Talk>>

JEE model questions and answers in English

Page: 1   
Mr.Love ™User is offline now
PM [1]
Rank : Helper
Status : Super Owner

#1
## JEE Model Questions (Physics, Chemistry, Mathematics)

Here are a few JEE model questions with answers and explanations across Physics, Chemistry, and Mathematics:

Physics:*

Question:

A ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height reached by the ball? (Take g = 10 m/s²

(A) 10 m


( 20 m
(C) 30 m
(D) 40 m

Answer:

( 20 m

Explanation:

We can use the following equation of motion: v² = u² + 2as. Here, v = final velocity (0 m/s at the highest point), u = initial velocity (20 m/s), a = acceleration (-10 m/s² since gravity acts downwards), and s = displacement (the maximum height).

0 = (20)² + 2(-10)s
0 = 400 - 20s
20s = 400
s = 20 m


Chemistry:*

Question:

Which of the following is an example of a redox reaction?

(A) NaCl + AgNO₃ → AgCl + NaNO₃

( CuO + H₂ → Cu + H₂O


(C) HCl + NaOH → NaCl + H₂O
(D) CaCO₃ → CaO + CO₂

Answer:

( CuO + H₂ → Cu + H₂O

Explanation:

In this reaction, CuO is reduced (Cu gains electrons, oxidation state changes from +2 to 0) and H₂ is oxidized (H loses electrons, oxidation state changes from 0 to +1). This simultaneous oxidation and reduction makes it a redox reaction.


Mathematics:*

Question:

Find the value of ∫₀¹ x² dx.

(A) 0
( 1
(C) 1/3


(D) 2/3


Answer:

(C) 1/3

Explanation:

The integral of x² is (x³/3. Evaluating this from 0 to 1 gives us:

[(1)³/3] - [(0)³/3] = 1/3 - 0 = 1/3.


More Challenging Example (Physics):*

Question:

A projectile is launched at an angle of 30° above the horizontal with an initial speed of 50 m/s. What is the horizontal range of the projectile? (Take g = 10 m/s²

(A) 216.5 m


( 108.3 m
(C) 250 m
(D) 125 m

Answer:

(A) 216.5 m

Explanation:

The horizontal range R is given by the formula: R = (u²sin(2&theta)/g, where u is the initial speed, θ is the launch angle, and g is the acceleration due to gravity.

R = (50² * sin(2 * 30°) / 10
R = (2500 * sin(60°) / 10
R = (2500 * (√3/2)) / 10
R ≈ 216.5 m



These are just a few examples. JEE questions cover a wide range of topics and difficulty levels. It's important to practice extensively and consult resources like previous year's papers and textbooks to thoroughly prepare for the exam. You can also find more practice questions online on various educational websites. Remember to focus on understanding the concepts and problem-solving techniques rather than memorizing formulas.

Reply
You are not logged in, please

Login

Page: 1   

Jump To Page:

Keywords:questions, answers, english, physics, chemistry, mathematics, explanations, across, question, thrown, vertically, upwards, velocity, maximum, height, reached,
Related threads:

"Why promises to farmers are not kept": Vice President to the Government


Surprise in Sambhal violence investigation: Police find 'Pak-made' bullets


E Shinde's push for last-minute deal amid preparations for Maharashtra swearing-in


Cyclone Fengal live: 7 dead in heavy rains in Tamil Nadu, PM assures support


E Shinde's push for last-minute deal amid preparation for Maharashtra swearing-in


What is the "bleeding eye" virus that has killed 15 people in Rwanda so far?


No rooms or meals for Bangladeshi tourists in Tripura: Hotel Association


Biden's move raises questions about US Department and action against Adani group


Ashwin's big comment on RCB captaincy after De Villiers' Kohli announcement


Premier League live: Liverpool leads 1-0, Man City eyes unwanted record


TERMS & CONDITIONS | DMCA POLICY | PRIVACY POLICY
Home | Top | Official Blog | Tools | Contact | Sitemap | Feed
Page generated in 0.22 microseconds
FRENDZ4M © 2024